Comments on: How To Draw The Enantiomer Of A Chiral Molecule https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/ Thu, 07 Dec 2023 23:23:40 +0000 hourly 1 https://wordpress.org/?v=6.6.2 By: How To Draw The Enantiomer Of A Chiral Molecule | Straight A Mindset https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-679081 Thu, 07 Dec 2023 23:23:40 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-679081 […] Two Ways To Draw The Enantiomer Of A Molecule With 1 Chiral Center […]

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By: Aditya https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-593210 Wed, 06 Jan 2021 03:07:41 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-593210 Very helpful indeed. Thanks

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By: James Ashenhurst https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-552487 Fri, 12 Apr 2019 19:11:31 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-552487 In reply to Samarth.

Start here: https://www.masterorganicchemistry.com/2016/10/20/introduction-to-assigning-r-and-s-the-cahn-ingold-prelog-rules/

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By: James Ashenhurst https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-552485 Fri, 12 Apr 2019 19:09:14 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-552485 In reply to hanna.

It will accurately show the change in configuration. However it will not accurately predict whether R is converted into S. I recommend doing this yourself on the substitution product.

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By: James Ashenhurst https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-552484 Fri, 12 Apr 2019 19:08:39 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-552484 In reply to hanna.

Obviously some thought has to go into it when applying it for SN2 reactions. The SN2 reaction will always invert stereochemistry, but it will not always convert R to S (or vice versa).

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By: Emily https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-540930 Sun, 21 Oct 2018 05:20:10 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-540930 I want to start off by saying thank you so much for your amazing website! It has been so helpful and I use it to prepare before every test! Is it valid to keep the “positions” of the substituents the same but change the wedges and dashes? So for example, if we had (S)-2-butanol could we make (R)-2-butanol by making the wedge of the OH group a dash and the dash of the H a wedge without doing any other swapping?

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By: Rohan Jangam https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-481498 Thu, 22 Sep 2016 12:59:58 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-481498 In reply to james.

This is because you used the other hand. The thumb rule works for only one hand – either left or right. If you use the other hand, the REVERSE is true. Hope you get what I’m saying.

I’m yet to go through this topic so couldn’t really tell you which hand is this particular direction true for. [This is similar to determining the direction of cross product of two vectors]

Thanks

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By: Samarth https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-454854 Sun, 17 Apr 2016 05:52:26 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-454854 In determining r and s configuration, with respect to what are we defining it clockwise or anticlockwise?I mean there could be many representations to the same substituents attack d to a carbon atom

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By: James https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-447156 Fri, 12 Feb 2016 19:06:31 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-447156 In reply to Alyx Vance.

Fixed. Thanks for letting me know.

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By: Alyx Vance https://www.masterorganicchemistry.com/2011/01/24/how-to-draw-enantiomer/#comment-445384 Mon, 25 Jan 2016 05:28:04 +0000 https://www.masterorganicchemistry.com/?p=1292#comment-445384 In reply to James.

I also just noticed that the Newman projection molecule on the left (just to the right of the two tartaric acid molecules) should have S configuration instead! When I converted the Newman projection to line-wedge drawing, the H is on a wedge, while OH is on a dashed bond. So I think that the real configuration should be reversed to S!

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